SplitScript reference / Module / path

Module.path

Method

Module.path() -> String!

Returns the module's host-provided filesystem path.

The path uses the runtime's portable filesystem spelling. It is metadata only: SplitScript does not grant scripts unrestricted host filesystem access.

Effects: reads process memory, requires an attached process

Runtime behavior: available while a process is attached, except in onDetach; synchronous

Examples

Inspect the executable path

let executable = await process.mainModule()
let path = executable.path() else "Unknown"